Optimal. Leaf size=432 \[ -\frac {f (a+b x)^m (c+d x)^{-m} \left (-a^2 d^2 f^2 \left (m^2+5 m+6\right )+2 a b d f (m+2) (c f m+3 d e)-\left (b^2 \left (-c^2 f^2 (1-m) m+6 c d e f m+6 d^2 e^2\right )\right )\right ) \, _2F_1\left (1,-m;1-m;\frac {(b e-a f) (c+d x)}{(d e-c f) (a+b x)}\right )}{2 m (b e-a f)^2 (d e-c f)^4}+\frac {d (a+b x)^{m+1} (c+d x)^{-m-1} \left (a^2 d^2 f^2 \left (m^2+5 m+6\right )-a b d f \left (c f \left (2 m^2+5 m+3\right )+d e (5 m+9)\right )+b^2 \left (-c^2 f^2 \left (1-m^2\right )+5 c d e f (m+1)+2 d^2 e^2\right )\right )}{2 (m+1) (b c-a d) (b e-a f)^2 (d e-c f)^3}-\frac {f (a+b x)^{m+1} (c+d x)^{-m-1} (b (4 d e-c f (1-m))-a d f (m+3))}{2 (e+f x) (b e-a f)^2 (d e-c f)^2}-\frac {f (a+b x)^{m+1} (c+d x)^{-m-1}}{2 (e+f x)^2 (b e-a f) (d e-c f)} \]
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Rubi [A] time = 0.57, antiderivative size = 452, normalized size of antiderivative = 1.05, number of steps used = 5, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {129, 151, 12, 131} \[ \frac {f (a+b x)^{m+1} (c+d x)^{-m-1} \left (-a^2 d^2 f^2 \left (m^2+5 m+6\right )+2 a b d f (m+2) (c f m+3 d e)+b^2 \left (-\left (-c^2 f^2 (1-m) m+6 c d e f m+6 d^2 e^2\right )\right )\right ) \, _2F_1\left (1,m+1;m+2;\frac {(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )}{2 (m+1) (b e-a f)^3 (d e-c f)^3}+\frac {f (a+b x)^{m+1} (c+d x)^{-m} \left (a^2 d^2 f^2 \left (m^2+5 m+6\right )-a b d f \left (c f \left (2 m^2+5 m+3\right )+d e (5 m+9)\right )+b^2 \left (-c^2 f^2 \left (1-m^2\right )+5 c d e f (m+1)+2 d^2 e^2\right )\right )}{2 (m+1) (e+f x) (b c-a d) (b e-a f)^2 (d e-c f)^3}+\frac {d (a+b x)^{m+1} (c+d x)^{-m-1}}{(m+1) (e+f x)^2 (b c-a d) (d e-c f)}+\frac {f (a+b x)^{m+1} (c+d x)^{-m} (-a d f (m+3)+b c f (m+1)+2 b d e)}{2 (m+1) (e+f x)^2 (b c-a d) (b e-a f) (d e-c f)^2} \]
Antiderivative was successfully verified.
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Rule 12
Rule 129
Rule 131
Rule 151
Rubi steps
\begin {align*} \int \frac {(a+b x)^m (c+d x)^{-2-m}}{(e+f x)^3} \, dx &=\frac {d (a+b x)^{1+m} (c+d x)^{-1-m}}{(b c-a d) (d e-c f) (1+m) (e+f x)^2}+\frac {\int \frac {(a+b x)^m (c+d x)^{-1-m} (-f (b c (1+m)-a d (3+m))+2 b d f x)}{(e+f x)^3} \, dx}{(b c-a d) (d e-c f) (1+m)}\\ &=\frac {d (a+b x)^{1+m} (c+d x)^{-1-m}}{(b c-a d) (d e-c f) (1+m) (e+f x)^2}+\frac {f (2 b d e+b c f (1+m)-a d f (3+m)) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f) (d e-c f)^2 (1+m) (e+f x)^2}-\frac {\int \frac {(a+b x)^m (c+d x)^{-1-m} \left (f \left (b^2 c (4 d e-c f (1-m)) (1+m)+a^2 d^2 f \left (6+5 m+m^2\right )-a b d (3+2 m) (2 d e+c f (1+m))\right )-b d f (2 b d e+b c f (1+m)-a d f (3+m)) x\right )}{(e+f x)^2} \, dx}{2 (b c-a d) (b e-a f) (d e-c f)^2 (1+m)}\\ &=\frac {d (a+b x)^{1+m} (c+d x)^{-1-m}}{(b c-a d) (d e-c f) (1+m) (e+f x)^2}+\frac {f (2 b d e+b c f (1+m)-a d f (3+m)) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f) (d e-c f)^2 (1+m) (e+f x)^2}+\frac {f \left (a^2 d^2 f^2 \left (6+5 m+m^2\right )+b^2 \left (2 d^2 e^2+5 c d e f (1+m)-c^2 f^2 \left (1-m^2\right )\right )-a b d f \left (d e (9+5 m)+c f \left (3+5 m+2 m^2\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f)^2 (d e-c f)^3 (1+m) (e+f x)}+\frac {\int \frac {(b c-a d) f (1+m) \left (2 a b d f (2+m) (3 d e+c f m)-b^2 \left (6 d^2 e^2+6 c d e f m-c^2 f^2 (1-m) m\right )-a^2 d^2 f^2 \left (6+5 m+m^2\right )\right ) (a+b x)^m (c+d x)^{-1-m}}{e+f x} \, dx}{2 (b c-a d) (b e-a f)^2 (d e-c f)^3 (1+m)}\\ &=\frac {d (a+b x)^{1+m} (c+d x)^{-1-m}}{(b c-a d) (d e-c f) (1+m) (e+f x)^2}+\frac {f (2 b d e+b c f (1+m)-a d f (3+m)) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f) (d e-c f)^2 (1+m) (e+f x)^2}+\frac {f \left (a^2 d^2 f^2 \left (6+5 m+m^2\right )+b^2 \left (2 d^2 e^2+5 c d e f (1+m)-c^2 f^2 \left (1-m^2\right )\right )-a b d f \left (d e (9+5 m)+c f \left (3+5 m+2 m^2\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f)^2 (d e-c f)^3 (1+m) (e+f x)}+\frac {\left (f \left (2 a b d f (2+m) (3 d e+c f m)-b^2 \left (6 d^2 e^2+6 c d e f m-c^2 f^2 (1-m) m\right )-a^2 d^2 f^2 \left (6+5 m+m^2\right )\right )\right ) \int \frac {(a+b x)^m (c+d x)^{-1-m}}{e+f x} \, dx}{2 (b e-a f)^2 (d e-c f)^3}\\ &=\frac {d (a+b x)^{1+m} (c+d x)^{-1-m}}{(b c-a d) (d e-c f) (1+m) (e+f x)^2}+\frac {f (2 b d e+b c f (1+m)-a d f (3+m)) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f) (d e-c f)^2 (1+m) (e+f x)^2}+\frac {f \left (a^2 d^2 f^2 \left (6+5 m+m^2\right )+b^2 \left (2 d^2 e^2+5 c d e f (1+m)-c^2 f^2 \left (1-m^2\right )\right )-a b d f \left (d e (9+5 m)+c f \left (3+5 m+2 m^2\right )\right )\right ) (a+b x)^{1+m} (c+d x)^{-m}}{2 (b c-a d) (b e-a f)^2 (d e-c f)^3 (1+m) (e+f x)}+\frac {f \left (2 a b d f (2+m) (3 d e+c f m)-b^2 \left (6 d^2 e^2+6 c d e f m-c^2 f^2 (1-m) m\right )-a^2 d^2 f^2 \left (6+5 m+m^2\right )\right ) (a+b x)^{1+m} (c+d x)^{-1-m} \, _2F_1\left (1,1+m;2+m;\frac {(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )}{2 (b e-a f)^3 (d e-c f)^3 (1+m)}\\ \end {align*}
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Mathematica [A] time = 1.05, size = 374, normalized size = 0.87 \[ -\frac {(a+b x)^{m+1} (c+d x)^{-m} \left ((e+f x) \left (f (b e-a f) \left (a^2 d^2 f^2 \left (m^2+5 m+6\right )-a b d f \left (c f \left (2 m^2+5 m+3\right )+d e (5 m+9)\right )+b^2 \left (c^2 f^2 \left (m^2-1\right )+5 c d e f (m+1)+2 d^2 e^2\right )\right )-\frac {f (e+f x) (b c-a d) \left (a^2 d^2 f^2 \left (m^2+5 m+6\right )-2 a b d f (m+2) (c f m+3 d e)+b^2 \left (c^2 f^2 (m-1) m+6 c d e f m+6 d^2 e^2\right )\right ) \, _2F_1\left (1,m+1;m+2;\frac {(d e-c f) (a+b x)}{(b e-a f) (c+d x)}\right )}{c+d x}\right )+f (b e-a f)^2 (d e-c f) (-a d f (m+3)+b c f (m+1)+2 b d e)+\frac {2 d (b e-a f)^3 (d e-c f)^2}{c+d x}\right )}{2 (m+1) (e+f x)^2 (b c-a d) (b e-a f)^3 (d e-c f)^2 (c f-d e)} \]
Antiderivative was successfully verified.
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fricas [F] time = 1.23, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (b x + a\right )}^{m} {\left (d x + c\right )}^{-m - 2}}{f^{3} x^{3} + 3 \, e f^{2} x^{2} + 3 \, e^{2} f x + e^{3}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x + a\right )}^{m} {\left (d x + c\right )}^{-m - 2}}{{\left (f x + e\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 0.24, size = 0, normalized size = 0.00 \[ \int \frac {\left (b x +a \right )^{m} \left (d x +c \right )^{-m -2}}{\left (f x +e \right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x + a\right )}^{m} {\left (d x + c\right )}^{-m - 2}}{{\left (f x + e\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (a+b\,x\right )}^m}{{\left (e+f\,x\right )}^3\,{\left (c+d\,x\right )}^{m+2}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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